SETTLEMENT TELEMETRY

Inference Logs

SETTLEMENT TELEMETRY

Inference Logs

Logs:30913 total
58 / 1031
Created / MID / TSTx MIDAliasobject_typeMode / Proto / FixregsVendor/LLMFlagsStatusEst. TokensTokensPriceContractCostToken UsageStop / ErrorLatencySummary
2026-09-09 18:15:26.293
2026-09-09 18:15:26.293
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Success
I: 114
C: -
O: 4,096
T: 4,210
I: 137
C: 0
O: 406
T: 543
137 × 1.35 = 0.000185
0 × 0.045 = 0.000000
406 × 4.05 = 0.001644
CNY 0.001829
—
137 × 1.2 = 0.000164
0 × 0.04 = 0.000000
406 × 3.6 = 0.001462
CNY 0.001626
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5.10s
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    "text": "请围绕下面的关键词写一段连贯的分析(约 80 tokens 的输入):latency distribution、结合实际案例、背后的设计取舍、背后的设计取舍、并给出可落地的建议、分布式系统、latency distribution、under high concurrency、token gener",
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    "text": "分布式系统中,token generation延迟分布需关注p99而非均值。高并发下,排队与批处理导致长尾,如流式输出偶发卡顿。设计取舍:大batch提吞吐但增尾延迟。可落地建议:动态批处理、按延迟SLO分级调度,以及基于分位数的自动扩缩容。",
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2026-09-09 18:15:22.936
2026-09-09 18:15:22.936
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Success
I: 114
C: -
O: 4,096
T: 4,210
I: 137
C: 0
O: 160
T: 297
137 × 1.35 = 0.000185
0 × 0.045 = 0.000000
160 × 4.05 = 0.000648
CNY 0.000833
—
137 × 1.2 = 0.000164
0 × 0.04 = 0.000000
160 × 3.6 = 0.000576
CNY 0.000740
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2.73s
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    "text": "请围绕下面的关键词写一段连贯的分析(约 80 tokens 的输入):latency distribution、结合实际案例、背后的设计取舍、背后的设计取舍、并给出可落地的建议、分布式系统、latency distribution、under high concurrency、token gener",
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    "text": "在高并发下分布式系统的 token generation 延迟分布常呈长尾:如某 LLM 服务 99% 请求在 200ms 内,但峰值尾延迟超过 2s,源于排队与资源争抢。设计取舍在于牺牲平均吞吐换取尾部稳定性,或反之。可落地建议:为生成任务拆分细粒度队列,限流并隔离高优先级请求,同时用容量预估和缓",
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2026-09-09 18:14:28.346
2026-09-09 18:14:28.346
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Success
I: 100
C: -
O: 4,096
T: 4,196
I: 87
C: 0
O: 54
T: 141
87 × 1.35 = 0.000117
0 × 0.045 = 0.000000
54 × 4.05 = 0.000219
CNY 0.000336
—
87 × 1.2 = 0.000104
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54 × 3.6 = 0.000194
CNY 0.000299
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1.68s
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    "text": "用一句话解释缓存",
    "has_image": false,
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    "text": "缓存就是临时把经常要用的数据放在更快、更近的地方,下次再用时不用重新算或重新找,从而省时间。",
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2026-09-09 18:14:26.133
2026-09-09 18:14:26.133
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I: 100
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O: 4,096
T: 4,196
I: 87
C: 0
O: 55
T: 142
87 × 1.35 = 0.000117
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55 × 4.05 = 0.000223
CNY 0.000340
—
87 × 1.2 = 0.000104
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55 × 3.6 = 0.000198
CNY 0.000302
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1.57s
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    "text": "用一句话解释缓存",
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    "text": "缓存就是:把常用的数据放在更近、更快的地方,下次用的时候不用再重新算或重新取,直接拿,省时间。",
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2026-09-09 18:13:43.527
2026-09-09 18:13:43.527
guvrYKDAwOF3Wjkvtx
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I: 100
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T: 4,196
I: 87
C: 0
O: 75
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87 × 1.35 = 0.000117
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75 × 4.05 = 0.000304
CNY 0.000421
—
87 × 1.2 = 0.000104
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75 × 3.6 = 0.000270
CNY 0.000374
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1.80s
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    "text": "缓存就是把常用的数据临时存到更快的存储位置,下次使用时直接获取,用空间换时间。",
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2026-09-09 18:13:40.724
2026-09-09 18:13:40.724
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I: 100
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I: 87
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87 × 1.35 = 0.000117
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81 × 4.05 = 0.000328
CNY 0.000446
—
87 × 1.2 = 0.000104
0 × 0.04 = 0.000000
81 × 3.6 = 0.000292
CNY 0.000396
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2026-09-09 18:12:16.669
2026-09-09 18:12:16.669
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Success
I: 100
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T: 4,196
I: 89
C: 0
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89 × 1.35 = 0.000120
0 × 0.045 = 0.000000
4459 × 4.05 = 0.0181
CNY 0.0182
—
89 × 1.2 = 0.000107
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4459 × 3.6 = 0.0161
CNY 0.0162
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    "text": "详细解释分布式系统的CAP定理",
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    "text": "CAP 定理是分布式系统领域最基础、也最常被误解的一个定理。  \n它由 Eric Brewer 在 2000 年提出,后来由 Gilbert 和 Lynch 给出形式化证明,也叫 **Brewer’s Theorem**。\n\n---\n\n## 1. CAP 定理简介\n\nCAP 说的是:在分布式系统中,",
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2026-09-09 18:11:35.010
2026-09-09 18:11:35.010
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119.61s
详细解释分布式系统的CAP定理
2026-09-09 18:10:34.856
2026-09-09 18:10:34.856
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I: 100
C: -
O: 4,096
T: 4,196
I: 89
C: 0
O: 10,641
T: 10,730
89 × 1.35 = 0.000120
0 × 0.045 = 0.000000
10641 × 4.05 = 0.0431
CNY 0.0432
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10641 × 3.6 = 0.0383
CNY 0.0384
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    "text": "# CAP 定理详解\n\nCAP 定理是分布式系统中最基本、也最常被误解的定理之一。它由 Eric Brewer 提出,后来由 Seth Gilbert 和 Nancy Lynch 给出严格证明。\n\n## 1. C、A、P 分别是什么?\n\n### C:Consistency(强一致性)\n\n不是“最终一",
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2026-09-09 18:10:13.834
2026-09-09 18:10:13.834
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C: -
O: 4,096
T: 4,196
I: 87
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O: 86
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86 × 4.05 = 0.000348
CNY 0.000466
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CNY 0.000414
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    "text": "缓存是把经常要用的数据临时存在更靠近使用方的位置,从而加快访问速度、减少延迟和降低后端压力。",
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2026-09-09 17:44:22.078
2026-09-09 17:44:22.078
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O: 4,096
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33 × 4.05 = 0.000134
CNY 0.000247
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CNY 0.000220
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2026-09-09 17:44:20.014
2026-09-09 17:44:20.014
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2026-09-09 17:17:13.315
2026-09-09 17:17:13.315
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CNY 0.000324
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CNY 0.000288
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2026-09-09 17:17:10.925
2026-09-09 17:17:10.925
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I: 100
C: -
O: 4,096
T: 4,196
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2026-09-09 17:16:34.050
2026-09-09 17:16:34.050
guvXwiZasU3uSvHdtx
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2026-09-09 17:16:31.746
2026-09-09 17:16:31.746
guvXviNlLd6BgKVjtx
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2026-09-09 17:16:12.208
2026-09-09 17:16:12.208
guvXovrp7qo3fGxZtx
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2026-09-09 16:55:46.214
2026-09-09 16:55:46.214
guvQoJzgzlpU4xPntx
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2026-09-09 16:55:44.301
2026-09-09 16:55:44.301
guvQncVbYyjBwimntx
deepseek-v4-flash-g3gucs9pn4RAHUO73lraxi-server:3300:v1.1.4013-14-gbfebabe6d
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2026-09-09 16:54:38.668
2026-09-09 16:54:38.668
guvQQFrMHPezZOn1tx
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2026-09-09 16:41:46.318
2026-09-09 16:41:46.318
guvM0YPkaWcGbuFJtx
deepseek-v4-flash-g3gucs9pn4RAHUO73lraxi-server:3300:v1.1.4013-14-gbfebabe6d
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2026-09-09 16:41:44.065
2026-09-09 16:41:44.065
guvLzp7DO5KvOaEVtx
deepseek-v4-flash-g3gucs9pn4RAHUO73lraxi-server:3300:v1.1.4013-14-gbfebabe6d
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2026-09-09 16:39:58.964
2026-09-09 16:39:58.964
guvLOKB0hj9FTZcntx
deepseek-v4-flash-g3gucs9pn4RAHUO73lraxi-server:3300:v1.1.4013-14-gbfebabe6d
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2026-09-09 16:39:56.770
2026-09-09 16:39:56.770
guvLNbCR5zgf271rtx
deepseek-v4-flash-g3gucs9pn4RAHUO73lraxi-server:3300:v1.1.4013-14-gbfebabe6d
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Success
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2026-09-09 16:08:47.861
2026-09-09 16:08:47.861
guvAh3NjkDtFKOUntx
deepseek-v4-pro-g3gucs9pv3TRoBtepNraxi-server:3300:v1.1.4013-14-gbfebabe6d
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Success
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2026-09-09 16:07:08.883
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guvA7xcXKq3iOdshtx
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2026-09-09 16:04:58.542
2026-09-09 16:04:58.542
guv9NqYQp8NtoYgztx
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Success
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2026-09-09 16:04:54.933
2026-09-09 16:04:54.933
guv9MSimmiLBD42ptx
deepseek-v4-pro-g3gucs9pv3TRoBtepNraxi-server:3300:v1.1.4013-14-gbfebabe6d
chat_completion
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Success
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2026-09-09 15:23:09.217
2026-09-09 15:23:09.217
guuv2O8BrNgSOTBttx
deepseek-v4-pro-g3gucs9pv3TRoBtepNraxi-server:3300:v1.1.4013-14-gbfebabe6d
chat_completion
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volcengine-bizplan-dtx/deepseek-v4-pro-ga-260813gtMyXDcWcENHaJLE/gtMyXDnAfH4svhhO
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Success
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}
length
22.85s
{
  "system_prefix": null,
  "history_count": 1,
  "user_summary": {
    "text": "请围绕下面的关键词写一段连贯的分析(约 100 tokens 的输入):性能优化、内存管理、结合实际案例、under high concurrency、内存管理、并给出可落地的建议、streaming response、机器学习、load balancing、背后的设计取舍、如何度量与验证、load",
    "has_image": false,
    "has_tool_result": false
  },
  "assistant_summary": {
    "text": "1. **性能优化与内存管理**:在 under high concurrency 下,结合实际案例(如机器学习推理服务),采用 **streaming response** 降低内存峰值,配合对象池/零拷贝减少 GC 压力。  \n2. **负载均衡与设计取舍**:通过 **load balanci",
    "tool_calls": [],
    "stop_reason": "length"
  }
}
2026-09-09 15:22:52.393
2026-09-09 15:22:52.393
guuuwNR9JFFZyJkhtx
deepseek-v4-pro-g3gucs9pv3TRoBtepNraxi-server:3300:v1.1.4013-14-gbfebabe6d
chat_completion
req-v1-chatcmplopenai-chatcmpl
volcengine-bizplan-dtx/deepseek-v4-pro-ga-260813gtMyXDcWcENHaJLE/gtMyXDnAfH4svhhO
STREAM
Success
I: 160
C: -
O: 4,096
T: 4,256
I: 150
C: 0
O: 1,344
T: 1,494
150 × 4.05 = 0.000607
0 × 0.135 = 0.000000
1344 × 12.15 = 0.0163
CNY 0.0169
—
150 × 3.6 = 0.000540
0 × 0.12 = 0.000000
1344 × 10.8 = 0.0145
CNY 0.0151
{
  "completion_tokens": 1344,
  "completion_tokens_details": {
    "reasoning_tokens": 1258
  },
  "prompt_tokens": 150,
  "prompt_tokens_details": {
    "cached_tokens": 0
  },
  "total_tokens": 1494
}
stop
21.98s
{
  "system_prefix": null,
  "history_count": 1,
  "user_summary": {
    "text": "请围绕下面的关键词写一段连贯的分析(约 100 tokens 的输入):可观测性、人工智能、请详细说明、并发控制、以及未来发展趋势、token generation、需要考虑的权衡、cache strategy、token generation、算法复杂度、分点阐述其中的、关键原理与影响、服务治理、",
    "has_image": false,
    "has_tool_result": false
  },
  "assistant_summary": {
    "text": "请详细说明,围绕人工智能服务治理,分点阐述其中的关键原理与影响:可观测性为并发控制提供决策依据;token generation的算法复杂度与 cache strategy 需考虑的权衡包括命中率、一致性与成本;token generation 延迟会放大并发竞争。以及未来发展趋势是 AI 原生可观",
    "tool_calls": [],
    "stop_reason": "stop"
  }
}
* Settlement log sourced from pgtk_inference_logs (ADR 211).Showing 30 of 30 entries
Logs: 30913
58 / 1031